1.1
Show that the choice γ = µ/2 minimizes the probability of error given by Eq. (10.26) (i.e., pe = 1 2Q µ−γ σ + 1 2Q γ σ ). Hint: The Q-function is continuously differentiabl
1.1
Show that the choice γ = µ/2 minimizes the probability of error given by Eq. (10.26) (i.e., pe = 1 2Q µ−γ σ + 1 2Q γ σ ). Hint: The Q-function is continuously differentiabl
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